W1Q1: Logically address an array

% Option 1 - My solution

v=A(:)==1;

% Option 2 - Also good

v=A==1; v(:);

% Option 3 - Some people used LOGICAL in weird ways, sometimes
  correctly, sometimes not, but never necessary! Here is one such
  example, which is correct 
v=A(logical(A))==1;

% Option 4 - Some people used RESHAPE in weird ways, sometimes correctly,
  sometimes not, but never necessary! Here are two  such
  examples, which is correct 
v=reshape(A==1,prod(size(A)),1);
v=reshape(A,[m*m,1])==1;
v=reshape(A==1,[size(A,1)*size(A,2),1]);

% Option 5 - Here's an example of using ALL unnecessarily that still
works since it's working in the second dimension of a one-dimensional
array, so effecticely it is the identity operation
v=all(A(:)==1,2)

% Option 6 - Here's an example of something that simply doesn't affect
the solution, using TRUE without reassigning the result to a variable
v=A(:)==1;
true(v');


W1Q2: Address a structure implicitly

% Option 1 - Stick in a number and a string
l=2;
q='ID';

% Option 2 - Overdone, using a logical
l=strcmp('Bob',{students.Name});
q='ID';

% Option 3 - Correct, while sinning against the "don't change the
  line below"
l=students(2);
q=l.ID;
% Shouldn't have changed the below
v=q


W1Q3: Learn from your figures 

The question is about learning FROM THE FIGURES. Not doing it by hand,
not removing the "clear variable" statement, not fudging it. There are
still a few different ways of doing it.

Option 1 - Simplest 

xl=xlim;
yl=ylim;
minAr=min(xl); maxAr=max(xl);
minAi=min(yl); maxAi=max(yl);
v=minAr+maxAr+minAi+maxAi;

Option 2 - Same thing, a tad more complicated

xl=get(gca,'xlim');
yl=get(gca,'ylim');
minAr=min(xl); maxAr=max(xl);
minAi=min(yl); maxAi=max(yl);
v=minAr+maxAr+minAi+maxAi;

Option 3 - Even more complicated 

h=findobj(gca,'Type','line');
x=get(h,'Xdata');
y=get(h,'Ydata');
xl=x(1);
yl=y(1);
minAr=min([xl{:}])
maxAr=max([xl{:}]);
minAi=min([yl{:}])
maxAi=max([yl{:}])
v= minAr + maxAr + minAi + maxAi;


W1Q4: Make a formatted string

Option 1 - Simple

v1=sprintf('%8.6f',notpi(1));
v2=sprintf('%8.6f',notpi(2));
v3=sprintf('%8.6f',pi);

Option 2 - Turns out you can be lucky with %f, but I don't rate this
as very good, since it relies on a MATLAB default

v1=sprintf('%f',notpi(1));
v2=sprintf('%f',notpi(2));
v3=sprintf('%f',pi);

Option 3 - Another way to get lucky, but I also don't like it much

v1=sprintf('%0.6f',notpi(1));
v2=sprintf('%0.6f',notpi(2));
v3=sprintf('%0.6f',pi);


W1Q5: Make an alphanumeric string

Option 1 - Right
v=sprintf('%ss birthday is %s %i',bdayn,bdayms,bdayd);

Option 2 - This is cheating! You're not using the database
v=sprintf('%s',bdayn,'s birthday is ',bdayms,' 5')